Chem hw problem help!!!?

54 g aluminium requires 213 grams Cl2 , but 2.7 grams aluminium need 10.65 grams Cl2, but the available chlorine is only 4.05 grams. Hence all the Cl2 react leaving behind some aluminium. Hence Cl2 is limiting reagent which is completely consume. 213 grams of Cl2 on complete reaction with aluminium gives 267 grams (2 x133.5) of AlCl3. 4.05 grams of Cl2 gives 5.08 grams of AlCl3. The molecular weight of AlCl3 is 133.5grams.